If y=3[x] +2= 2[x+4] - Find value of [x+y]
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To Prove ∑nr=03r×Crn=4n by binomial expansion
(a+b)n=C0nanb0+C1nan−1b1....Cnna0bn=
∑nr=0Crn×an−r×br
if
we compare the two terms
∑nr=03r×Crn=∑nr=0Crn×an−r×br
hence if we make a=1 and b=3
we get ∑nr=0Crn×1n−r×3r
which is same as given term,
∑nr=03r×Crn
putting the same values in (a+b)n=(1+3)n=4n is the answer
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