If y^3. x^5 = (x+y)^8
, then dx
/dy
is
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1
Answer:
[8(x+y)^7-5x^4y^3]/3x^5y
Step-by-step explanation:
x^5.d/dx(y^3)+(y^3)5x^4=d/dx(x+y)^7
x^5×3y.dy/dx+(y^3)5x^4=8(x+y)^7
dy/dx=[8(x+y)^7-5x^4.y^3]/3x^5y[proved]
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