Math, asked by sakshisharma4600, 3 months ago

If y^3. x^5 = (x+y)^8

, then dx
/dy

is​

Answers

Answered by arkasaha085
1

Answer:

[8(x+y)^7-5x^4y^3]/3x^5y

Step-by-step explanation:

x^5.d/dx(y^3)+(y^3)5x^4=d/dx(x+y)^7

x^5×3y.dy/dx+(y^3)5x^4=8(x+y)^7

dy/dx=[8(x+y)^7-5x^4.y^3]/3x^5y[proved]

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