If y=(3x+2)(2x-1), then find dy/dx
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Explanation:
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Answered by
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Explanation:
u = 3×+2
u = 2×-1
dy = d/x [3×+2] [2×-1]
d[uu]/dx = u/du/dx + u/du/dx
dy/dx = [3×+2] d/dx [2×-1] 3
= [3×+2] [2] + [2×-1] 3
=6×+4+6×-3=12×+1
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