If y=3X +2x+6 then
dy/dx =
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Step-by-step explanation:
y=3x\²+2x
\begin{gathered}\displaystyle{\sf{\frac{dy}{dx}=\frac{d}{dx}(3x^2+2x) }}\\\\\displaystyle{\sf{=3.\frac{d}{dx}(x^2)+2.\frac{d}{dx}(x) }}\\\\\displaystyle{\sf{(Linear\ differentiation)}}\\\\\displaystyle{\sf{=3.2x+2.1}}\\\\\displaystyle{\sf{=6x+2}}\end{gathered}
dx
dy
=
dx
d
(3x
2
+2x)
=3.
dx
d
(x
2
)+2.
dx
d
(x)
(Linear differentiation)
=3.2x+2.1
=6x+2
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