Question

if y= 3x+x-100 then dy\dx is :
(A).6x
(B).6x+1
(C).6x+1-100
(D).x³+x²-100x​

Answer 1

Wrong question !!!

Correct question : y = 3x² + x – 100

$y = 3x {}^{2} + x - 100$

$\frac{dy}{dx} = 6x + 1$

( B ) is the correct answer.