If y (3x - y) : x (4x + y) = 5 : 12, find (x2 + y2) : (x + y)2. Answer in proper explanation and i will mark you as the brainiest.....
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Answer:
25/49
Step-by-step explanation:
Given
If y(3x-y):x(4x+y)= 5:12, then find the ratio (x^2+y^2):(x+y)^2
So we need to find the ratio. So product of means is equal to product of extremes.
So 12 y(3 x – y) = 5 x(4 x + y)
36xy – 12y^2 = 20x^2 + 5xy
36xy – 5xy = 20x^2 + 12 y^2
31xy = 20x^2 + 12y^2
20x^2 – 31xy + 12 y^2 = 0
20x^2 – 16 xy – 15 xy + 12y^2 = 0
4x(5x – 4y) – 3y(5x – 4y) = 0
5x – 4y = 0 4x – 3y = 0
5x = 4y 4x = 3y
x = 4y / 5 x = 3y / 4
Now we need to find
x ^2 + y^2 / (x + y)^2
Substituting for x we get
x = 4 y/5
16 y^2 / 25 + y^2 / (9 y / 5)^2
41 y^2 / 25 / 81 y^2 / 25
= 41 / 81
When x =3 y/4 we get
9 y^2 / 16 + y^2 / (7y / 4)^2
= 25 y^2 / 16 / 49 y^2 / 16
= 25 / 49
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