Question

If y = 3x2 - 2x + 1, find the value of x for which y'=0.


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Answer 1

y = 3x^2 - 2x + 1

y' = 6x - 2

y'(0) = 6*0 - 2

y'(0) = -2

hope it helped you

Answer 2

Hope this would be helpful.