Question

if y=3xsquare then calculate the slope of tangent of y vs x at graph x=2​

Answer 1

Answer:

Eq of the curve, y = 3x^2 - x + 1

Slope, dy/dx = 6x -1

Slope at (1,3) = 6×1 - 1 = 5

We know the tangent eq or eq of straight line is, y = mx + C

Put the values, m = 5 , (1,3)

3 = 5×1 + C

c = 3–5 = -2

Therefore, eq of tangent is

y = mx + C

y = 5x - 2 (ans)