Question

If √y=√4-√6, then find y²-20y+12​

Answer 1

Answer:

56

Step-by-step explanation:

If,√y= √4-√6

then, y= 4-6

then, y= -2

then, y^2= 4

so,

y^2-20y+12

=4-20(-2)+12

=4+40+12

=56

Answer 2

Step-by-step explanation:

√y=√4-6

y²-20y+12=[(√4-6)*(√4-6)]-(20*√4-6)+12

=(√-2)²-(20*√-2)+12.

=>> now {(√-2)²} will be cut

=-(√-40)+12. (-*-=+)

=√ 40+12

=6.324

=6.32. (avg.)