Question

If y = 4x^3 + 2x² +6/x+3, then find dy/dx =?

Answer 1

y=x2−2x+2x4+4

⇒dxdy=(x2−2x+2)2(x2−2x+2)(4x3)−(4x4+4)(2x−2)

∴(dxdy)x=21=(41+1)2(41+1)(4×81)+(161+4)=2575=3