if y=5^(log x) then (dy)/(dx)=
Please answer fast with explanation
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3
here is ur answer:
Taking log of both sides we get
Log y= logxlog5
Differentiating wrt x
dy/dx *1/y=log 5*x.
dy/dx=y/x log5
d
Answered by
2
taking log of both sides we get
log y = log x. log 5
differentiate w. r. t X
dy/dx * 1/y = log 5*x
dy/dx = y/x log 5
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