Question

if y=500e^7x+600e^-7x then dy/dx is?

Answer 1

$y = 500 {e}^{7x} + 600 {e}^{ - 7x}$

$\dfrac{dy}{dx} = 500. \dfrac{d}{dx}( {e}^{7x} ) + 600. \dfrac{d}{dx} ( {e}^{ - 7x} )$

$\implies \: 3500 {e}^{7x} - 4200 {e}^{ - 7x}$

$\therefore \: \dfrac{dy}{dx} = 3500 {e}^{7x} - 4200 {e}^{ - 7x}$