Question

if y= 5x^2+6x+7/2x^2+3x+4 find dy/dx​

Answer 1

Answer:

Please Check the attachment

Answer 2

Step-by-step explanation:

$y = 5 {x}^{2} + 6x + \frac{7}{2} {x}^{2} + 3x + 4 \\ = \frac{17}{2} {x}^{2} + 9x + 4$

$\frac{dy}{dx} = \frac{17}{2} \times \frac{d}{dx}( {x) + 9 \frac{d}{dx} }^{} (x) + 4 \\ = \frac{17}{2} \times 2 {x}^{1} + 9 + 4 \\ \: = \frac{34}{2} x + 13 \\ = 17x + 13$