Question

If y=5x^3/2 and t=2(x)^1/2 find dy/dt
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Answer 1

Answer:

I'm not absolutely sure on how I can deal with this problem with this problem:

Find dydx if y=2u2−3u and u=4x−1

I am trying to use the chain rule on it..

dydx=dydududx

My work so far:

ddu(2u2−3u)∗ddx(4x−1)=(4u−3)(4)