Question

if y= 5x³-2logx+3ex, find dy/dx​

Answer 1

Answer:

Y = e^(2logx + 3x)

Taking log both sides

Log (y) = loge^ (2logx + 3x)

Log (y) = (2logx + 3x) log e

Log (y) = 2logx + 3x

Differentiating both sides with respect to x

(1 / y) (dy/dx) = 2 / x + 3

dy/dx = (2/x + 3) y

dy/dx = (2/x + 3)(2logx +3x)

Hope it helps :)