Math, asked by krishangi30, 10 months ago

if y=7 then find (5y+15/y)(25y^2-75+225/y^2)​

Answers

Answered by Anonymous
2

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y = 7 \\  \\ (5y +  \frac{15}{y} )(25 {y}^{2}  - 75 +  \frac{225}{ {y}^{2} })

(25 {y}^{2}  - 75 +  \frac{225}{ {y}^{2} } )

( {5y}^{2}   +  { (\frac{15}{y} )}^{2} - 75)

   { (5y -  \frac{15}{y} )}^{2}

Put in question

(5y  +  \frac{15}{y} )(5y -  \frac{15}{y} )(5y -  \frac{15}{y} )

( {5y}^{2}  - ( \frac{15}{y} )^{2} (5y -  \frac{15}{y} )

Put value of y

(25 \times 49) - ( \frac{225}{49} )(5 \times 7 - \frac{15}{7} )

( \frac{60025 - 225}{49} )( \frac{1715 - 15}{49} )

 \frac{59800}{49}  \times  \frac{1700}{49}

 \frac{101,660,000}{2401}

42,340.691378592 \:  \:  \: ans \:

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Answered by kishore200403
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