Question

If y= a cos(log x) prove that x^2 y2 + xy1 +y =0
Soln:- y1 = a dcos(log x) /dlogx *dlogx/dx
= -a sin (logx)/x
y2= (-ax dsin(logx)/dlogx*dlogx/dx+ a(sin(logx)) .dx/dx)/x^2
=( -axcos (logx)/x + asin(logx))/x^2
= -axcos(logx) + ax sin(logx)/x^3
= -acos(logx) + asin(logx)/x^2
To taken L.H.S.
-acos(logx) + asin(logx) - a sin(logx) + a cos(logx)
= 0 Proved

Answer 1

Step-by-step explanation:

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