Question

If y -a is a factor of y3 – 3y2a + 2a²y + b, then the value of bis:​

Answer 1

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Answer 2

(y-a) is a factor of p(y) = y³ - 3y²a + 2a²y + b,

So y = a is a zero of the polynomial p(y)

$p(a) = a^3-(3a^2*a)+(2a^2*a) + b = 0$

$p(a) = a^3-3a^3+2a^3+b = 0$

$p(a) = b = 0$

$\large\black\boxed{b=0}$