if y=a^x+x^a+a^a+√x then dy/dx
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y=
a
x
+
x
a
dx
dy
=
2
1
x
a
×
a
1
−
2
1
a
x
×
x
2
a
⇒
dx
dy
=
2
1
ax
1
−
2
1
x
a
×
x
1
2x(
dx
dy
)=(
a
x
−
x
a
)
2xy(
dx
dy
)=y(
a
x
−
x
a
)=(
a
x
+
x
a
)(
a
x
−
x
a
)⇒2xy(
dx
dy
)=(
a
x
−
x
a
)
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