if y=a^x+x^a+a^a+√x then dy/dx
Answers
Answered by
0
Step-by-step explanation:
Answer
y=
a
x
+
x
a
dx
dy
=
2
1
x
a
×
a
1
−
2
1
a
x
×
x
2
a
⇒
dx
dy
=
2
1
ax
1
−
2
1
x
a
×
x
1
2x(
dx
dy
)=(
a
x
−
x
a
)
2xy(
dx
dy
)=y(
a
x
−
x
a
)=(
a
x
+
x
a
)(
a
x
−
x
a
)⇒2xy(
dx
dy
)=(
a
x
−
x
a
Answered by
0
Step-by-step explanation:
x. dy/dx(a) + a. dy/dx(x) + a. dy/dx(a)+1/2.x raised to -1/2
differentiation of constant is 0
that's why 0+a+0+1/2.x raised to -1/2
ans is a + 0.5/rootx
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