Question

If Y and B represent Young's modulus and bulk
modulus for a material, then in practice:
(a) Y<3B
(b) Y = 3B
(c) Y > 3B
(d) B = 3Y​

Answer 1

Answer:

option c is rhe answer hope it helps u

Answer 2

The required "option (a) Y < 3B".

Explanation:

We have,

Young's modulus  for a material = Y and  bulk  modulus for a material = B

We know that,

$\dfrac{Y}{3B}$ = 1 - 2$\sigma$  ... (1)

Since, $\sigma$ is lies between 0 and $\dfrac{1}{2}$.

∴ 0 < 1 - 2$\sigma$ < 1                            ... (2)

From (1) and (2), we get

⇒ $\dfrac{Y}{3B}$ < 1

⇒Y < 3B

Hence, the required "option (a) Y < 3B".