If Y and Z are the bisectors of base angles Y and Z of angle triangle xyz and if angle x is equal to 62 degree find the measure of angle YOZ.
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Answer:
∠yoz = 121°
Step-by-step explanation:
in Δ xyz
∠y + ∠z + ∠x = 180°
=> ∠y + ∠z + 62° = 180°
=> ∠y + ∠z = 118°
Bisector of ∠y & ∠z meets at O
∠zyo = ∠y/2
∠yzo = ∠z/2
in Δ yoz
∠zyo + ∠yzo + ∠yoz = 180°
=> ∠y/2 + ∠z/2 + ∠yoz = 180°
=> (∠y + ∠z )/2 + ∠yoz = 180°
=> 118°/2 + ∠yoz = 180°
=> 59° + ∠yoz = 180°
=> ∠yoz = 121°
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