if y = b tan^-1 (x/a + tan^-1 y/x)
Find dy/dx
Answers
Answered by
2
Explanation:
y=btan
−1
(
a
x
+tan
−1
x
y
)
b
y
=tan
−1
(
a
x
+tan
−1
x
y
)
tan
b
y
=
a
x
+tan
−1
x
y
Differentiating both sides w.r.t. x, we get,
b
1
sec
2
(
b
y
)
dx
dy
=
a
1
+
1+(
x
y
)
2
1
×
x
2
x
dx
dy
−y
b
1
sec
2
(
b
y
)
dx
dy
=
a
1
+
x
2
+y
2
x
dx
dy
−y
dx
dy
[
b
1
sec
2
(
b
y
)−
x
2
+y
2
x
]=
a
1
−
x
2
+y
2
y
Therefore,
dx
dy
=
b
1
sec
2
(
b
y
)−
x
2
+y
2
x
a
1
−
x
2
+y
2
y
Answered by
1
Explanation:
see the attachment......
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