if y=cos^-1(cosx) then dy/dt×atx= 5π/4 is equal to
Answers
Answered by
1
Step-by-step explanation:
Given,
y=cos
−1
cosx
dx
dy
=
dx
d
(cos
−1
(cos(x)))
Let f=cos
−1
(u),u=cos(x)
=
du
d
(cos
−1
(u))
dx
d
(cos(x))
=(−
1−u
2
1
)(−sin(x))
=(−
1−cos
2
(x)
1
)(−sin(x))
∴
dx
dy
=
sin
2
(x)
sin(x)
dx
dy
x=
4
5π
=
sin
2
(
4
5π
)
sin(
4
5π
)
=
1−cos(
2
π
)
2
sin(
4
5π
)
=
1−0
2
(−
2
2
)
=−1
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Answered by
2
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y=cos
−1
cosx
dx
dy
=
dx
d
(cos
−1
(cos(x)))
Let f=cos −1 (u),u=cos(x)
= dud (cos
−1 (u)) dxd (cos(x))
=(− 1−u 21 )(−sin(x))
=(− 1−cos 2
(x)
1 )(−sin(x))
∴ dxdy = sin 2 (x)
sin(x)
dxdy
x= 45π
= sin 2 ( 45π )
sin( 45π )
= 1−cos( 2π )2 sin( 45π )
= 1−02
(− 22 )
=−1
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