Question

if y = cos-1x , find d2y/dx2 in term of y alone​

Answer 1

Answer:

1. y=cos(-1x). = cos x
2. dy/dx = -sinx
3. d2y/dx2= -cosx

from y=cos(-x)

x=-cos–(y)

then

d2y/dx2=-cos {-cos–(y)}

d2y/dx2 = y

Answer 2

Answer:

y=cos(-1x). = cos x

dy/dx = -sinx

d2y/dx2= -cosx

from y=cos(-x)

x=-cos–(y)

then

d2y/dx2=-cos {-cos–(y)}

d2y/dx2 = y

Step-by-step explanation: