if y = cos-1x , find d2y/dx2 in term of y alone
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Answer:
- y=cos(-1x). = cos x
- dy/dx = -sinx
- d2y/dx2= -cosx
from y=cos(-x)
x=-cos–(y)
then
d2y/dx2=-cos {-cos–(y)}
d2y/dx2 = y
Answered by
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Answer:
y=cos(-1x). = cos x
dy/dx = -sinx
d2y/dx2= -cosx
from y=cos(-x)
x=-cos–(y)
then
d2y/dx2=-cos {-cos–(y)}
d2y/dx2 = y
Step-by-step explanation:
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