if y=cos^2(3x/2)-sin^2(3x/2),then d^2y/d^2x
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Answer:y=cos
2
2
3x
−sin
2
2
3x
=cos(2×
2
3x
)=cos3x
dx
dy
=−3sin3x
dx
2
d
2
y
=−9cos3x=−9y
Step-by-step explanation:
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