Question

if y=cos(2x²+x) find dy/dx​

Answer 1

Answer:

=cos

−1

(2x

2

−1)&z=cos

−1

x

dz

dy

=

dz/dx

dy/dx

y=cos

−1

(2x

2

−1)

dx

dy

=

1−(2x

2

−1)

2

−1

×[4x−0]

dx

dy

=

1−4x

2

−1+4x

2

−1∗4x

=

2x

1−x

2

−4x

dx

dy

=

1−x

2

−2

⟶1

z=cos

−1

x

dx

dz

=

1−x

2

−1

⟶2

From equation 1 and 2

dz

dy

=

−1/

1−x

2

−2/

1−x

2

=2