Question

if Y=cos inverse of (4x^3 - 3x)then show that dy/dx= -3/√1-x^2​

Answer 1

Answer:

dy/dx=-sin(4x^3-3x).d/dx(4x^3-3x)

=-sin(4x^3-3x).(4.3x^3-1 -3)

=-sin(4x^3-3x).(12x^2 -3)