Question

if y=√cos then find dy/dx​

Answer 1

Step-by-step explanation:

y =√ cosx

dy/ DX = d√cosx / d y/√cos

d*√cos*x/ d*y/√cos

cos = dy/ dx

Answer 2

Answer

Step-by-step explanation';

$\frac{dy}{dx}$⇔$\frac{d\sqrt{cosx} }{dx}$                       ∴$\frac{dy}{dx}=nx^{n-1}$

                                         ∴$\frac{dcosx}{dx}=-sinx$

by chain rule,

   ⇒$\frac{1}{2 }cosx^{(\frac{1}{2}-1) }$*(-sinx)

   ⇒-$\frac{sinx}{2\sqrt{cosx} }$