Question

If y=cosec (cot √x),then find dy / dx.

Answer 1

Answer:

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Explanation:

Answer 2

Given:

• A equation $y = cosec[cot \sqrt{x} ]$ is given

To Find:

• Differentiation of the equation.

Solution:

Let          $y = cosec[cot \sqrt{x} ]$

Differentiate with respect to x

⇒   $\frac{dy}{dx} = - cot[cot \sqrt{x} ] . cosec[cot \sqrt{x} ] \times \frac{d[cot \sqrt{x} ] }{dx}$

⇒   $\frac{dy}{dx} = - cot[cot \sqrt{x} ] . cosec[cot \sqrt{x} ] \times [- cosec^2\sqrt{x} ] \times \frac{1}{2\sqrt{x} }$

⇒    $\frac{dy}{dx} = \frac{cot[cot \sqrt{x} ] . cosec[cot \sqrt{x} ] . (cosec^2\sqrt{x})}{2\sqrt{x} }$