Question

if y=cosx/1+sinx then find dy/dx​

Answer 1

Answer:

yer yeah cosh theta sin theta

Step-by-step explanation:

eska beta uska beta mujhe mat pucho

Answer 2

Answer:

Hey! I can help you.

Step-by-step explanation:

This can be done by using u/v rule.

y= cosx/1+sinx

After differentiating w.r.t x.

dy/dx = (1+sinx)d/dx(cosx) - (cosx)d/dx(1+sinx) /(1+sinx)^2

dy/dx = (1+sinx)(-sinx) - (cosx)(cosx) / (1+sinx)^2

dy/dx = -sinx-sin^2x - cos^2x / (1+sinx)^2

dy/dx = -sinx-(sin^2x+cos^2x) / (1+sinx)^2

dy/dx = -sinx-1 /(1+sinx)^2

dy/dx = -1/1+sinx

Hope it helps you.

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