Question

if y=√cosx find dy/dx​

Answer 1

Answer:

-sinx/2√cosx

Step-by-step explanation:

(dy/dx)=d(√cosx)/dx

= 1/2(cosx^(-1/2)×dcosx/dx

= 1/2(√cosx) × (-sinx)

= sinx/2√cosx

Answer 2

$y = \sqrt{cosx} \\ \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{cosx} } \frac{d}{dx} cosx \\ \\ \frac{dy}{dx} = \frac{ - sinx}{2 \sqrt{cosx} }$