Question

if y=cosx/tanx then dy/dx=?

Answer 1

Answer:

1. cosx (tan^-1)
2. diff. with respect to x
3. Dy/DX=-sinxd/DX tan^-1x
4. Dy/DX=-sinx/1+x^2

Answer 2

Answer:

-[cot(x)+cos(x)]

Explanation

cosx/tanx= (cosx)^2/sinx

= cosecx-sinx

so,d(cosecx-sinx)/dx

=-cotx-cosx