if y=cosx/tanx then dy/dx=?
Answers
Answered by
1
Answer:
- cosx (tan^-1)
- diff. with respect to x
- Dy/DX=-sinxd/DX tan^-1x
- Dy/DX=-sinx/1+x^2
Answered by
0
Answer:
-[cot(x)+cos(x)]
Explanation
cosx/tanx= (cosx)^2/sinx
= cosecx-sinx
so,d(cosecx-sinx)/dx
=-cotx-cosx
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