if y = cot^-1(1-x/2+x) w.r.t. x,then dy/dx is
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If y=cot
−1
(1+x
2
−x), then
dx
dy
=
Medium
Solution
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Correct option is
A
1+x
2
1
+
1+(x−1)
2
1
dx
d
[cot
−1
(1+x
2
−x)]
Let u=1+x
2
−x⇒dx=2x−1
=
du
d
(cot
−1
(u))
dx
d
(1+x
2
−x)...(1)
∵
du
d
(cot
−1
(u))=
u
2
+1
−1
&
dx
d
(1+x
2
−x)=2x−1
putting these values in eq
n
(1)
=(
u
2
+1
−1
)(2x−1)
=(
(1+x
2
−x)
2
+1
−1
)(2x−1)
=
x
4
−2x
3
+3x
2
−2x+2
−(2x−1)
Answer
solution
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