if y=e^(5logx) then value of dy/dx is? please tell me the process
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Answered by
12
dy/dx = d/dx {e^(5logx)}
dy/dx = e^(5logx) × d/dx (5logx) {∵ d/dx (e^x) = e^x}
dy/dx = e^(5logx) × 5/x {∵ d/dx (logx) = 1/x}
dy/dx = 5e^(5logx)/x is the answer
dy/dx = e^(5logx) × d/dx (5logx) {∵ d/dx (e^x) = e^x}
dy/dx = e^(5logx) × 5/x {∵ d/dx (logx) = 1/x}
dy/dx = 5e^(5logx)/x is the answer
Answered by
16
But the answer given in my book is 5x⁴.
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