Question

If y = e' log, (x) then dx​

Answer 1

Answer:

dy/dx=1

Explanation:

y=e^(logx)

Differentiating,

dy/dx=d/dx(e^(logx))

dy/dx=e^(logx) × 1/x

dy/dx=x × 1/x (e^(logx)=x)

dy/dx=1

Answer 2

Given,

y = e^log(x)

To Find,

The value of dy/dx

Solution,

The given function is

y = e^log(x)

taking log base e both sides

log(y) = log(x)*log(e)  { using the property log m^n = n*log(m)}

log(y) = log(x)*1  {log e = 1}

Now, taking antilog both sides

y = x

dy = dx

dy/dx = 1

Hence, the value of dy/dx = 1.