Math, asked by dragonstac5159, 9 months ago

If y=e^logx prove that dy/dx=1

Answers

Answered by sus9
2

Answer:

given

y=e^logx ......1eqn

we have to diff.eqn 1 w. r.t"x"

then

dy/dx=d/dx(e^logx)........2eqn

because diff of e(x)=e(x)

therefore,eqn 2become

dy/dx=e^logx d/dx(logx)

dy/dx=e^logx×1/x......3eqn

because diff.of ex/diff of x=1

therefore eqn 3 becomes

dy/dx=1

HOPE IT WILL HELP YOU IN YOUR STUDY'S ✌️

Answered by manvanjabha
0

Answer:

Hope this helps you.

y=x

differentiate on both sides wrt x

dy/dx=1

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