If y=e^logx prove that dy/dx=1
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Answered by
2
Answer:
given
y=e^logx ......1eqn
we have to diff.eqn 1 w. r.t"x"
then
dy/dx=d/dx(e^logx)........2eqn
because diff of e(x)=e(x)
therefore,eqn 2become
dy/dx=e^logx d/dx(logx)
dy/dx=e^logx×1/x......3eqn
because diff.of ex/diff of x=1
therefore eqn 3 becomes
dy/dx=1
HOPE IT WILL HELP YOU IN YOUR STUDY'S ✌️
Answered by
0
Answer:
Hope this helps you.
y=x
differentiate on both sides wrt x
dy/dx=1
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