Question

If Y=.e^x logx then find dy/dx
(A) e^x. 1/z
(B)e^x .1/x + log x.e^x
(C) ex log x
(D) x log x + e^x​

Answer 1

Answer:

If Y=.e^x logx then find dy/dx

a^logb bace c = b^loga bace c

y=x^logc base e

y=x

dy/dx=1