Question

if y equals to sin x + log x square + e power 2 X then DY by DX will be​

Answer 1

Solution :

Given, $\mathrm{y=sinx+logx^{2}+e^{2x}}$

$\to \mathrm{y=sinx+2logx+e^{2x}}$

Differentiating both sides w.r.t. x, we get

$\mathrm{\frac{dy}{dx}=\frac{d}{dx}(sinx+2logx+e^{2x})}$

$\to \mathrm{\frac{dy}{dx}=\frac{d}{dx}(sinx)+2\frac{d}{dx}(logx)+\frac{d}{dx}(e^{2x})}$

$\to \boxed{\mathrm{\frac{dy}{dx}=cosx+\frac{2}{x}+2e^{2x}}}$

Rules :

• $\mathrm{\frac{d}{dx}(sinmx)=m\:cosmx}$

• $\mathrm{\frac{d}{dx}(logx)=\frac{1}{x}}$

• $\mathrm{\frac{d}{dx}(e^{mx})=m\:e^{mx}}$

Answer 2

Answer:

hope it helps uh.. ....