Question

If y = ex + 1, than prove that: y’’– y’ = 0.​

Answer 1

Answer:

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differentiation problem

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Answer 2

Answer:

Solution

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e

y

(x+1)=1

e

y

×1+[e

y

×

dx

dy

×(x+1)]=0

Differentiating on both sides

⇒

dx

dy

=

e

y

×(x+1)

−e

y

=

x+1

−1

Differentiating again

⇒

dx

2

d

2

y

=

−(x+1)

2

−1

=

(x+1)

2

1

⇒

dx

2

d

2

y

=

(x+1)

2

1

=(

x+1

−1

)

2

=(

dx

dy

)

2

Hence proved

Step-by-step explanation:

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