If y = f(x) =x+2/x-1, x, y # 1 then x is equal to
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0
Answer:
1/y =x−1/x+2
y(x−1)=(x+2)×1
yx−y=x+2,yx−x=2+y
x(y−1)=2+y
or x=
y−1
2+y
Answered by
1
Answer:
y = f (x) = [x + 2] / [x – 1]
f (y) = [y + 2] / [y – 1]
yx – y = x + 2
yx – x = 2 + y
x = [2 + y] / [y – 1] = f (y)
f (1) is not defined.
f ‘(x) > 0; f (x) is increasing
f ‘(x) < 0; f (x) is decreasing
f (x) = [x + 2] / [x – 1]
f’ (x) = {[x – 1] – [x + 2]} / (x – 1)2.
= -3 / (x – 1)2
f ‘(x) < 0; f (x) is decreasing
Domain x ∈ R – {1}
Step-by-step explanation:
Hope it's helpful!!!!
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