If y=f(x² +2) and f'(3)=5,then dy/dx at x=1
Answers
Answered by
4
Step-by-step explanation:
Given, y=f(x
2
+2)
On differentiating both sides w.r.t. x, we get
dx
dy
=f
′
(x
2
+2)×2x
Put x=1, we get
dx
dy
=f
′
(1
2
+2)×2=f
′
(3)×2
=5×2 [∵f
′
(3)=5] given
=10
Answered by
2
Answer:
Step-by-step explanation:
Given, y=f(x
2
+2)
On differentiating both sides w.r.t. x, we get
dx
dy
=f
′
(x
2
+2)×2x
Put x=1, we get
dx
dy
=f
′
(1
2
+2)×2=f
′
(3)×2
=5×2 [∵f
′
(3)=5] given
=10
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