Question

If Y is a number suchthat y=x, where x is a positive integer, what is the differwncebetween largest possible two digit value of y and the smalles possinle three digit value of Y

Answer 1

Answer:

x is a positive integer , it's highest value 9 .

so, 9×9=81 , so (2 digit) largest value of y=81

when x=10 y=xx=10×10=100 , which is smalles three digit value of x

So, difference 100–81=19