If y is directly proportional to 1/x and x=2 when y=20 what is the value of x when y =125?
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y is directly proportional to 1/x
⇒⇒⇒y₁/y₂ =1/x₁/1/x₂ =x₂/x₁
y₁/y₂=x₂/x₁
x₁=2 , y₁=20 , y₂=125 , x₂=?
20/125=x₂/2
x₂=40/125=8/25
y is directly proportional to 1/x
⇒⇒⇒y₁/y₂ =1/x₁/1/x₂ =x₂/x₁
y₁/y₂=x₂/x₁
x₁=2 , y₁=20 , y₂=125 , x₂=?
20/125=x₂/2
x₂=40/125=8/25
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