If y is equal to the sum of x, 4, and 2x, by how much does y exceed 3x ?
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When the value of x is equal to 3 and the y is equal to 5,
3x^2 – 2y
=> 3*3^2 - 2*5
=> 3*9 - 10 = 17
And 2x^2– 3y
=> 2*3^2 - 3*5
=> 2* 9 - 15 = 3
This gives 3x^2 – 2y exceeding 2x^2– 3y by 17 - 3 = 14
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