Question

If y=⅔ is one of the root of the equation 3y²—ky+8=0 then find the value of k​

Answer 1

Answer:

Putting the value of y = 2/3

we get :

3 (2/3) ^2 - k (2/3) + 8 =0

3 (4/9) - 2/3 k +8 =0

4/3 - 2/3 k +8= 0

k = 14

Answer 2

Answer:

3*(2/3)^2-k*2/3+8=0

3*4/9-2/3k+8=0

4/3+8-2/3k=0

-2/3k=-28/3

k=14