Math, asked by arunaya, 6 months ago

If y, is the ku derivative of y with respect to x, y = cos(sinx) then y1sinx + y2cosx =
a) ysin^3x
b) -ysin^3x
c) ycos^3x
d) -ycos ^3x

Answers

Answered by SonalRamteke

2

If y, is the ku derivative of y with respect to x, y = cos(sinx) then y1sinx + y2cosx =

a) ysin^3x

b) -ysin^3x

c) ycos^3x

d) -ycos ^3x

ycos³x

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