Question

If y = log
(1- x^2/
1 + x^2)
then find
dy/dx​

Answer 1

Answer:

y=ln(1-x^2)-ln(1+x^2)

dy/dx= 1/(1-x^2) d/dx(-2x) - 1/(1+x^) d/dx(2x)

dy/dx=-2x/(1-x^2) - 2x/(1+2x)

dy/dx= -4x/(1-x^4)