Question

if y= log (3x²+2x+1) then find dy/dx​

Answer 1

Answer:

(6x+2)/(3x^2+2x+1)

Step-by-step explanation:

y= log(3x^2+2x+1)

apply chain rule

dy/dx= (1/3x^2+2x+1) (6x+2)

(6x+2)/(3x^2+2x+1)

hope it helps u

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