If y = log (5x square +3x +2 ) then find dy by dx
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first differentiate log and then the polynomial
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Y=log(5x^2+3x+2)....given
therefore , diff^n b.s w.r.x.
dy/dx=d/dxl[og(5x^2+3x+2)]
By chain rule,
=(1/5x^2+3x+2)*d/dx(5x^2+3x+2)
=[10x+3/5x^2+3x+2]
therefore , diff^n b.s w.r.x.
dy/dx=d/dxl[og(5x^2+3x+2)]
By chain rule,
=(1/5x^2+3x+2)*d/dx(5x^2+3x+2)
=[10x+3/5x^2+3x+2]
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