Question

If y = log (5x square +3x +2 ) then find dy by dx

Answer 1

first differentiate log and then the polynomial

Answer 2

Y=log(5x^2+3x+2)....given
therefore , diff^n b.s w.r.x.
dy/dx=d/dxl[og(5x^2+3x+2)]
         By chain rule,
         =(1/5x^2+3x+2)*d/dx(5x^2+3x+2)
        =[10x+3/5x^2+3x+2]